You don't need to cast the result of malloc in a C program. As to your question, you can just compile an example program and see for yourself. As others have answered, yes, they are the same. sizeof(3) is a bit weird, too.
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printf("root is at %g with residual %g \n", x, fcn(x));. convert that line from C to C++. I got this: cout << "Root is at %g with residual %g \n" << x << fcn(x) << endl;. However the output is: "Root is at %g with residual %g ...
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